Not applicable
Jan 12, 2018
07:49 AM
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Jan 12, 2018
07:49 AM
Hi, I'm trying to figure out how to use an H-Bridge driver chip without resorting to the boot strap cap method. The FETs themselves are switching a +96V circuit, and what I'd like to do is connect a +108V signal directly to Vboost. Is this possible? What other considerations do I need to make or take into account?
Thanks, Dan B.
Thanks, Dan B.
Solved! Go to Solution.
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ispn:14106:1:0
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l1:144:1:0
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l2:1244:1:0
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- IFX
1 Solution
Jan 26, 2018
12:44 AM
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Jan 26, 2018
12:44 AM
Hello Dan,
The AGND should be connected to DGND for this IC. And please add a small capacitor between Vb and Vs as a filter.
The AGND should be connected to DGND for this IC. And please add a small capacitor between Vb and Vs as a filter.
3 Replies
Jan 22, 2018
10:03 PM
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Jan 22, 2018
10:03 PM
so yo mean no bootstrap circuit is used in your application, and use a 108V connected to the VB pin, 96V to VS pin. Then please use a capacitor between VB and VS as a filter, the IC will work as expected.
Not applicable
Jan 25, 2018
11:44 AM
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Jan 25, 2018
11:44 AM
Hi tengD, thanks for getting back to me. Here is the circuit I have now:
I'm going to add an isolated DC-DC converter to the circuit. And if I understand correctly, I should connect it like this?
Thanks again! Dan B.
I'm going to add an isolated DC-DC converter to the circuit. And if I understand correctly, I should connect it like this?
Thanks again! Dan B.
Jan 26, 2018
12:44 AM
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Jan 26, 2018
12:44 AM
Hello Dan,
The AGND should be connected to DGND for this IC. And please add a small capacitor between Vb and Vs as a filter.
The AGND should be connected to DGND for this IC. And please add a small capacitor between Vb and Vs as a filter.