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Thread: 2ED2183S06F Gate driver bootstrap capacitor calculation

  1. #1
    New Member New Member anuj@feup is on a distinguished road
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    2ED2183S06F Gate driver bootstrap capacitor calculation

    I am using the IPP016N08NF2S MOSFET in a synchornous buck converter. I am willing to use the 2ED2183S06F gate driver IC and i am not able to figure out what should be the bootstrap capacitor.

    As per the datasheet(https://www.infineon.com/dgdl/Infine...6cb8d765b229f7, page 14 ) of the gate driver,
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    I have confusion regarding the ∆VBS is the maximum allowable voltage drop at the bootstrap capacitor within a switching period, typically 1 V.
    But if we use the formula of the ∆VBS ≤ (VCC – VF– VGSmin– VDSon), It is impossible to get the 1V for me.

    How to deal with that.
    I am supplying around 15V to the gate driver. It must have a maximum duty cycle of 99.99% and switching frequency of 100KHz.

  2. #2
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    Abhilash P is on a distinguished road
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    Hi,

    After considering the formula from the datasheet and the variables that you have mentioned, I could arrive at Vbs<1V

    Qg = 170nC
    Qls = 1nC
    Iqbs = 170uA
    Ilkgs = 10nA
    Ilk = 1uA
    Thon = T * D = 9.9uS

    Qgtot = 170n + 1n + (170u + 10n + 1u)*9.9u
    19.692uC

    Hence to get Vbs <1v, the bootstrap capacitance must be less than or equal to Qgtot.

    Please let me know if you have further queries.

    Regards,
    Abhilash P
    The views expressed here are my personal opinions, have not been reviewed or authorized by Infineon and do not necessarily represent the views of Infineon.

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